NAME
strtoul - convert a string to an unsigned long integer
SYNOPSIS
#include <stdlib.h>
#include <limits.h>
unsigned long strtoul(const char *nptr, char **endptr, int base);
DESCRIPTION
Strtoul converts the string in nptr to an unsigned long
value
according to the given base, which must be between 2 and 36
inclusive, or be the special value 0.
The string may begin with an
arbitrary amount of white space (as
determined by isspace; see ctype(3)), followed by a single
optional
‘+’ or ‘-’ sign. If base is zero or
16, the string may then
include a ‘0x’ prefix, and the number will be
read in base 16;
otherwise, a zero base is taken as 10 (decimal) unless the
next
character is ‘0’, in which case it is taken as 8
(octal).
The remainder of the string is
converted to an unsigned long value
in the obvious manner, stopping at the end of the string or
at the
first character that does not produce a valid digit in the
given
base. (In bases above 10, the letter ‘A’ in
either upper or lower
case represents 10, ‘B’ represents 11, and so
forth, with ‘Z’
representing 35.)
If endptr is non nil, strtoul
stores the address of the first
invalid character in *endptr. If there were no digits at
all,
however, strtoul stores the original value of nptr in
*endptr.
(Thus, if *nptr is not ’ ’ but **endptr is
’ ’ on return, the
entire string was valid.)
RETURN VALUE
Strtoul returns either the result of the conversion or, if
there
was a leading minus sign, the negation of the result of the
conversion, unless the original (non-negated) value would
overflow;
in the latter case, strtoul returns ULONG_MAX and sets errno
to
ERANGE.
ERRORS
[ERANGE]
The given string was out of range; the value converted has
been clamped.
SEE ALSO
strtol(3)
STANDARDS
Strtoul conforms to ANSI X3.159-1989 ("ANSI
C").
BUGS
Ignores the current locale.